20x^2y^2+9xy-20=

Solution for 20x^2y^2+9xy-20= equation:

Simplifying
20x2y2 + 9xy + -20 = 0

Reorder the terms:
-20 + 9xy + 20x2y2 = 0

Solving
-20 + 9xy + 20x2y2 = 0

Solving for variable 'x'.

Factor a trinomial.
(-5 + -4xy)(4 + -5xy) = 0

Subproblem 1
Set the factor '(-5 + -4xy)' equal to zero and attempt to solve:

Simplifying
-5 + -4xy = 0

Solving
-5 + -4xy = 0

Move all terms containing x to the left, all other terms to the right.

Add '5' to each side of the equation.
-5 + 5 + -4xy = 0 + 5

Combine like terms: -5 + 5 = 0
0 + -4xy = 0 + 5
-4xy = 0 + 5

Combine like terms: 0 + 5 = 5
-4xy = 5

Divide each side by '-4y'.
x = -1.25y-1

Simplifying
x = -1.25y-1
Subproblem 2
Set the factor '(4 + -5xy)' equal to zero and attempt to solve:

Simplifying
4 + -5xy = 0

Solving
4 + -5xy = 0

Move all terms containing x to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + -4 + -5xy = 0 + -4

Combine like terms: 4 + -4 = 0
0 + -5xy = 0 + -4
-5xy = 0 + -4

Combine like terms: 0 + -4 = -4
-5xy = -4

Divide each side by '-5y'.
x = 0.8y-1

Simplifying
x = 0.8y-1
Solution
x = {-1.25y-1, 0.8y-1}